Penjelasan dengan langkah-langkah:
f(x)= (x+3)(2x-1)
f(x) = x(2x - 1) + 3(2x - 1)
= 2x² - x + 6x - 3
= 2x² + 5x - 3
f'(x) = 2.2x²-¹ + 5 - 0
f"(x) = 4.1x¹-¹ + 0
f"(x) = 4x⁰
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Penjelasan dengan langkah-langkah:
f(x)= (x+3)(2x-1)
f(x) = x(2x - 1) + 3(2x - 1)
= 2x² - x + 6x - 3
= 2x² + 5x - 3
f'(x) = 2.2x²-¹ + 5 - 0
f'(x) = 4x + 5
f"(x) = 4.1x¹-¹ + 0
f"(x) = 4x⁰
f"(x) = 4