Question

F(x) = (x²+1)cos²(x)
f'(π) = ?

yang bisa bantu dong, pake caranya ya^^ makasiih

Answer 1

Diketahui f(x) = (x²+1)cos²x.
Misalkan u = (x²+1) dan v = cos²x. => u'(x) = 2x dan v'(x) = -sin2x.
=> f'(x) = u'(x)v(x) + u(x)v'(x)
=> f'(x) = 2xcos²x - (x²+1)sin2x
=> f'(π) = 2πcos²π - (π² + 1)sin2π
=> f'(π) = (2π * 1) - (π² + 1)*0
=> f'(π) = 2π

Answer 2

cara ada pada lampiran yah !!