" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
f(1) = - 3 maka p - q = - 3 ... (1)
f(4) = 3 maka 4p - q = 3 ... (2)
eliminasi (1) dan (2) :
p - q = - 3
4p - q = 3
_________ -
- 3p = - 6
p = 2
q = 5
rumus fungsi: f(x) = 2x - 5
f(1) = -3
p(1) - q = -3
p-q = -3
p = q-3
q = p+3.........[1]
f(4) = 3
p(4) - q = 3
4p-q = 3 ...........[2]
substitusi [1] ke [2] didapat
4p-(p+3) = 3
4p-p-3=3
3p=3+3
3p=6
p=2
subst p=2 ke [1] didapat
q = 2 +3=5
jadi, p=2 q=5
rumus fungsi :
f(x) = px - q
f(x) = 2x-5