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f(3)= 7
f(5)= 15
f(-2)= ?
f(3)= a(3) + b= 7 ----> 3a + b= 7
f(5)= a(5) + b= 15 ----> 5a + b= 15 _
-2a= -8
a= -8/-2
a= 4
3a + b= 7
3(4) + b= 7
12 + b= 7
b= 7 - 12
b= -5
Maka, f(-2) :
f(-2)= a(-2) + b
= 4(-2) + (-5)
= -8 - 5
= -13
Jadi, f(-2)= -13.
F(3) = 3a + b = 7 ( x diganti 3)
F(5) = 5a + b = 15 ( x diganti 5)
Dieleminasi = -2a = -8
a = 4
F(3) = 3.4 + b = 7
12 + b = 7
b = -5
F(-2) = a.-2 + b
4.-2 + (-5)
-8 -5
F(-2) = -13