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f(2) = 2a + b = 1
f(4) = 4a + b = 7
menggunakan sistem eliminasi yang menghasilkan a = 3 dan b = -5
maka nilai a + 2b = 3 + (-10) = -7
1=2a+b
F(4)=a(4)+b
7=4a+b
4a+b=7
2a+b=1
----------- - (dikurangi)
2a =6
a =3
2(a)+b=1
2(3)+b=1
6+b=1
b=1-6
b=(-5)
a+2b = 3+2(-5)
= 3-10
= 7
maaf kalo kepanjangan