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D => 2q=48-p =>p=48-2q (pers.2)
P1 = P2
q+6 = 48-2q
q+2q = 48-6
3q = 42
q = 14
mencari nilai p=>
p = q+6
p = 14+6
p = 20
Keseimbangan pasar ada di titik (Q,P) = (14,20)
Good Luck! :D
persamaan 1 = Q = p-6
---------------- 2 = 2Q = 48-p
Q = 24 - 1/2p
p-6 = 24 - 1/2p
p + 1/2p = 24 + 6
3/2 p = 30
p = 30 x 2 : 3
= 20
harga keseimbangan = 20
Q = p - 6
= 20 - 6
= 14
jumlah barang keseimbangan terjadi jika permintaan 14 dan penawaran