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f(-2)=-2m +n=1 ∫ x1 ∫ -2m + n = 1
------------------- +
3n = -3
n = -1
m + n = -2
m + (-1) = -2
m = -1
rumus fungsi = f(x) = -1x - 1
f (-2) = -2m + n = 1