Question

Fungsi linear dengan f(x) =ax+1 dan f(6)=4 maka nilai f(-2) adalah

Answer 1

F(x) = ax + 1

f(6) = 4
6a + 1 = 4
6a = 3
a = 1/2

berarti
f(x) = (1/2)x + 1

f(-2)
= (1/2)-2 + 1
= -1 + 1
= 0

semoga benar yaa... ;-)

Answer 2

6a+1=4
6a=3
a=½

f(-2)=½×(-2)+1
=-1+1
=0