PEMBAHASAN
Fungsi Kuadrat
• Puncak P(xp , yp) → P(-2,3)
y = f(x) = a(x - xp)² + yp
f(x) = a(x + 2)² + 3
• melalui (1,12)
f(1) = 12
a(x + 2)² + 3 = 12
a(1 + 2)² = 12 - 3
9a = 9
a = 1
Rumus fungsi kuadrat :
f(x) = 1(x + 2)² + 3
f(x) = x² + 4x + 4 + 3
f(x) = x² + 4x + 7
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Verified answer
PEMBAHASAN
Fungsi Kuadrat
• Puncak P(xp , yp) → P(-2,3)
y = f(x) = a(x - xp)² + yp
f(x) = a(x + 2)² + 3
• melalui (1,12)
f(1) = 12
a(x + 2)² + 3 = 12
a(1 + 2)² = 12 - 3
9a = 9
a = 1
Rumus fungsi kuadrat :
f(x) = 1(x + 2)² + 3
f(x) = x² + 4x + 4 + 3
f(x) = x² + 4x + 7