" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Verified answer
H(x) = px + qh(2) = 1
2p+q=1
h (4) = 5
4p+q=5
cara eliminasi
4p+q=5
2p+q=1 --->dikurang
2p=4
p=2
2p+q=1
4+q=1
q=-3
h(10)=10p+q
h(10)=20+(-3)
h(10)=17
h(2) = 2p + q
h(2) = 1
2p + q = 1 ---> (i)
h(4) = 4p + q
h(4) = 5
4p + q = 5 ---> (ii)
Eliminasi (ii) - (i)
2p = 4
p = 2
2p + q = 1
2.2 + q = 1
4 + q = 1
q = -3
h(10) = 2.10 + (-3) = 17