Question

Fungsi h dinyatakan dengan rumus h(x)= ax+b . Jika h(5) = 16 dan h (4) = 11 . Nilai h(-1) adalah?

Answer 1

H(x) = ax+b
h(5) = 5a + b = 16
h(4) = 4a + b = 11
a = 5

5(5) + b = 16
25 + b = 16
b = 16-25
b = -9


Jadi h(-1) = ax+b
= 5(-1) + -9
= -5 + -9 = -14

Answer 2

H(5) = 5a + b = 16
h(4) = 4a + b = 11 (dikurangi
         a = 5

4a + b = 11
4(5) + b = 11
20 + b = 11
b = -9

h(-1) = ax + b
           5(-1) + (-9) = -14