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f(-3)=3(-3)-5=-14
f(-2)=-11
f(-1)=-8
f(0)=-5
f(1)=-2
f(2)=1
daerah hasilnya adalah {-14,-11,-8,-5,-2,1}
f(-3) = 3(-3) -5
= -9 -5 = -14
f(-2) = 3(-2) -5
= -6 -5 = -11
f(-1) = 3(-1) -5
= -3 -5 = -8
f(0) = 3(0) -5
= -5
f(1) = 3(1) -5
= 3 -5 = -2
f(2) = 3(2) -5
= 6 -5 = 1
Jadi, daerah hasil fungsinya = {-14, -11, -8, -5, -2, 1}.