Question

Fungsi f ditentukan oleh f(x) = ax + b. Jika pasangan pasangan berurutan (p, -3), (-3, q), (r, 2), (2, -2), dan (-2, 6) adalah anggota dari fungsi itu, nilai p, q, dan r adalah

Answer 1

Verified answer

F(x) = ax + b

cari a dan b nya dulu
(2,-2)
f(2) = ax + b = -2
= a(2) + b = -2
= 2a + b = -2 (persamaan pertama)
(-2,6)
f(-2) = ax + b = 6
= a(-2) + b = 6
= -2a + b = 6 (persamaan kedua)
Eliminasi persamaan pertama dan kedua
2a+b = -2
-2a+b = 6
------------- (dikurangin)
2a-(-2a) + b-b = -2-6
4a = -8
a = -8/4
a = -2
Subtitusi a=-2 ke persamaan pertama
2a+b = -2
2(-2) + b = -2
-4 + b = -2
b = -2 + 4
b = 2

f(x) = ax + b = -2x + 2

(p,-3)
f(p) = -2(p) + 2 = -3
= -2p + 2 = -3
= -2p = -3-2
= -2p = -5
= p = 5/2
(-3,q)
f(-3) = -2(-3) + 2 = q
= 6 + 2 = q
= q = 8
(r,2)
f(r) = -2(r) + 2 = 2
= -2r + 2 = 2
= -2r = 2-2
= -2r = 0
= r = 0/-2
= r = 0