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Ambil 2 titik yang sudah berupa bilangan asli
(2,-2) (-2,6)
f(x) = ax + b f(x) = ax + b
f(2) = 2a + b f(-2) = -2a + b
2a +b = -2 -2a +b = 6
Menggunakan cara eleminasi
2a + b = -2
-2a + b = 6
-2a - b = 2
-2a + b = 6
-4a = 8
a = -2
2a + b = -2
2(-2) + b = -2
b = -2+4
b = 2
Masukkan a dan b ke rumus fungsi
f(x) = ax +b
f(x) = -2x + 2
(p,-3) (-3,q)
Mencari nilai p dan q
f(x) = -3
f(x) = -2x + 2
-2x + 2 = -3
-2x = -3-2
-2x = -5
x = 5
2
p = 5
2
f(-3) = q
f(x) = -2x + 2
f(-3) = -2(-3) + 2
f(-3) = 6 + 2
f(-3) = 8
q = 8