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3a + b = 9
2b = -6
b = -3
3a+b = 9
3a -3 = 9
3a = 12
a = 4
f(x) = 4x -3
f(-2) = 4(-2) - 3 = -8 - 3 = -11
f(2) = 4(2) - 3 = 8 - 3 = 5
f(-2) + f(2) = -11 + 5 = -6
f(-3)=-3a+b
-15=-3a+b.........(pers.1)
f(3)=3a+b
9 =3a+b..........(pers.2)
eliminasi:
-3a+b=-15
3a+b=9
dikurang/ditambah untuk menghilangkan b/a
ditambah:
2b=-6
b =-3
subsitusikan nilai b ke salah stu pers.
3a+b=9
3a+(-3)=9
3a =12
a =4
rumus fungsi:
f(x)=ax+b
f(x)=4x+(-3)
#f(-2)=4x-3
=4(-2)-3
=-8-3
=-11
#f(2)=4x-3
=4(2)-3
=8-3
=5
f(-2)+f(2)=-11+5=-6