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f (x+2) = 3(x+2) - 5 = 3x + 6 - 5 = 3x + 1
f (2x-1) = 3(2x-1) - 5 = 6x - 3 - 5 = 6x -8
f (-x+5) = 3(-x+5) - 5 = -3x + 15 - 5 =-3x + 10
no 2
f (a+2) = f (2a-1)
3(a+2) - 5 = 3 (2a-1) - 5
3a + 6 - 5 = 6a - 3 - 5
3a +1 = 6a -8
3a - 6a = -8 -1
-3a =-9
a=3