" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
f(2) = a(2) + b = 3
= 2a + b = 3
f(-3) = 13
f(-3) = a(-3) + b = 13
= -3a + b =13
eliminasi di sibtitusikan
2a + b = 3 2a + b = 3
-3a + b = 13 2(3,2) + b = 3
dikurangi 6,4 + b =3
5a = 16 b = 3 - 6,4
a = 3,2 b = -3,4
jadi -a + b = -3,2 - 3,4
= 6,6
f(2) = 3 --> 2a + b = 3
f(-3) = 13 -->-3a + b = 13
eliminasi
2a + b = 3
-3a + b = 13 -
5a = -10
a = -2
subtitusi
a= -2 --> 2a + b = -10
2(-2) + b = -10
-4 + b = -10
b = -10 +4
b = -6
jadi -a + b = -(-2) + (-6)
= 4 - 6
= -2