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f(3) = a(3) +b = 11
= 3a +b = 11
f(1) = a(1) +b = 7
= a +b = 7
3a +b = 11
a +b = 7 -
2a = 4
a = 2
3a +b = 11
3(2) +b = 11
6 +b = 11
b = 11 -6
b = 5
Jadi, nila a = 2 dan b = 5.
b. a +2b
= 2 +2(5)
= 2 +10
= 12
F(3) = a(3)+b = 11 => 3a +b =11
F(1) = a(1)+b = 7 => a + b =7
===========> 2a = 4 (b-nya hilang karena smua di kurangin atau substitusi)
=> a = 2
a+b =7
2+b = 7
b = 5
B. a+2b = 2+2(5) = 2+10 = 20