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f(2)=2m+n=11
eliminasi
-1m+n=2
2m+n=11
--------- -
-3m = -9
m = 3
substitusi ke -1m+n=2
-1.3+n=2
-3+n=2
n=5
rumusnya
f(x)= 3x+5
f(4)=3.4+5=17