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f(-3 = a(-3) +b = -15
= -3a +b = -15
f(2) = a(2) +b = 0
= 2a +b = 0
-3a +b = -15
2a +b = 0 -
-5a = -15
a = 3
-3a +b = -15
-3(3) +b = -15
-9 +b = -15
b = -15 +9
b = -6
f(x) = 3x +(-6)
f(-5) = 3(-5) +(-6)
= -15 +(-6)
= -21
Itu jawabannya.
dit: f(-5)=...?
jaawab:
f(-3)=> ax+b=-15
=> -3a+b= -15
f(2) => ax+b = 0
=> 2a+b=0
eliminasi,
-3a+b=-15
2a+b=0 -
-5a =-15
a = -15/-5
a = 3
substitusi a= 3
2a+b=0
2(3)+b=0
6 + b =0
b = -6
f(-5)= ax+b
f(-5)= 3(-5) + (-6)
f(-5)= -15 -6
f(-5)= -21
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