Question

Fungsi di rumuskan dengan f(x) = ax+b
jika f(2) = 1 dan f (4) = 5 nilai x(10)

Answer 1

F(2) = 2a + b = 1
f(4) = 4a + b = 5
   -------------------- - dikurangi
      - 2a = -4
        a = 2, dan b = -3
jadi f(10) = 10.2 - 3 = 17

Answer 2

F(2) = 2a + b = 1
f(4) = 4a + b = 5
____________ -
-4a = -4
a = -4
      -4
a = 1

f(2) = 2x1 + b = 1
f(2) = 2 + b = 1
b = -1

f(10) = 1x10 + (-1)
f(10) = 10-1
f(10) = 9