Question

Fraksi mol glukosa (mr=180) dalam larutan glukosa 80% massa di dalam air adalah

Answer 1

Misal massa total = 100 gram
80% massa = 80 gram
massa air = 100 - 80 = 20 gram

mr glukosa = 180
massa glukosa = 80
mol glukosa = 180 / 80
= 2.25 mol

mr air = 18
massa air = 20 
mol air = 20 / 18 = 1.11 mol

fraksi mol glukosa = mol glukosa / mol glukosa + mol air
= 2.25 / 2.25 + 1.11
= 0.67