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Zadanie w załączniku ; )
Dane:F=20N
s=3m
α=30
t=10s
Oblicz:W=?P=?Rozwiązanie:
F = 20N
s = 3m
α = 30°
t = 10s
P = ?
W = ?
W = F x s x cosα
W = 20N x 3m x cos30° ≈ 52J
P = W/t
P = 52J/10s = 5,2W
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Feci, quod potui, faciant meliora potentes
Pozdrawiam :)
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Dane:
F=20N
s=3m
α=30
t=10s
Oblicz:
W=?
P=?
Rozwiązanie:
F = 20N
s = 3m
α = 30°
t = 10s
P = ?
W = ?
W = F x s x cosα
W = 20N x 3m x cos30° ≈ 52J
P = W/t
P = 52J/10s = 5,2W
----------------------------------------------------------------------------------------------------------
Feci, quod potui, faciant meliora potentes
Pozdrawiam :)