Penjelasan:
Hukum Kirchhoff 2 tentang tegangan menyatakan bahwa jumlah aljabar perubahan tegangan yang mengelilingi suatu rangkaian tertutup (loop) sama dengan 0.
Sigma V = 0
Sigma GGL + Sigma (I.R) = 0
Buat arah putaran I saling berlawanan arah
I3 = I1+I2...(1)
Loop kiri
-6 + 3I1 + 3I3 = 0
3.(I1+I3) = 6
I1+I3 = 2...(2)
Loop kanan
-6 + 3I3 + 6I2 = 0
3.(I3+2I2) = 6
I3+2I2 = 2...(3)
Substitusi (1) ke (2)
2I3-I2 = 2...(4)
Substitusi-Eliminasi (3) dan (4)
I3+2I2 = 2 × 2
2I3-I2 = 2 × 1
2I3+4I2 = 4
2I3-I2 = 2 -
-----------------------
5I2 = 2
I2 = 2/5 A
(3)
I3+2I2 = 2
I3+2.2/5 = 2
I3 = 2-4/5 = 6/5 A
(1)
I3 = I1+I2
6/5 = I1+2/5
I1 = 4/5 A
Jadi I1 = 0,8 A; I2 = 0,4 A; I3 = 1,2 A
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Penjelasan:
Hukum Kirchhoff 2 tentang tegangan menyatakan bahwa jumlah aljabar perubahan tegangan yang mengelilingi suatu rangkaian tertutup (loop) sama dengan 0.
Sigma V = 0
Sigma GGL + Sigma (I.R) = 0
Buat arah putaran I saling berlawanan arah
I3 = I1+I2...(1)
Loop kiri
-6 + 3I1 + 3I3 = 0
3.(I1+I3) = 6
I1+I3 = 2...(2)
Loop kanan
-6 + 3I3 + 6I2 = 0
3.(I3+2I2) = 6
I3+2I2 = 2...(3)
Substitusi (1) ke (2)
2I3-I2 = 2...(4)
Substitusi-Eliminasi (3) dan (4)
I3+2I2 = 2 × 2
2I3-I2 = 2 × 1
2I3+4I2 = 4
2I3-I2 = 2 -
-----------------------
5I2 = 2
I2 = 2/5 A
(3)
I3+2I2 = 2
I3+2.2/5 = 2
I3 = 2-4/5 = 6/5 A
(1)
I3 = I1+I2
6/5 = I1+2/5
I1 = 4/5 A
Jadi I1 = 0,8 A; I2 = 0,4 A; I3 = 1,2 A