n = 200 buah
d = 30 cm = 0,3 m
r = d/2 = 30/2 = 15 cm = 0,15 m
t = 20 cm = 0,2 m
s (sisi miring kerucut)
= √r² + t²
= √(0,15)² + (0,2)²
= √0,0225 + 0,04
= √0,0625
= 0,25 m
Luas topi kerucut:
= phi x r x s
= 3,14 x 0,15 x 0,25
= 0,11775 m²
Luas karton:
= luas kerucut x n
= 0,11775 x 200
= 23,55 m² (b)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
n = 200 buah
d = 30 cm = 0,3 m
r = d/2 = 30/2 = 15 cm = 0,15 m
t = 20 cm = 0,2 m
s (sisi miring kerucut)
= √r² + t²
= √(0,15)² + (0,2)²
= √0,0225 + 0,04
= √0,0625
= 0,25 m
Luas topi kerucut:
= phi x r x s
= 3,14 x 0,15 x 0,25
= 0,11775 m²
Luas karton:
= luas kerucut x n
= 0,11775 x 200
= 23,55 m² (b)
Luas Kerucut
s = √15²+20²
s = √225+400
s = √625
s = 25cm
luas selimut kerucut = 22/7 x 15 x 25 = 1178,57cm² = 11,78m² x 200
= 2356cm²
= 23,56m²
Luas permukaan
3,14x 15 (25+15) = 1884cm² x 200
= 376800cm²
= 37,68m²
Wassalamu'alaikum Wr.Wb
Guru Matematika IPA Terpadu
Mr. Hendro