Fanny tolong yah by. Rome.... Question from @IIRomeII

May 2019 1 6 Report

Fanny tolong yah by. Rome

fanny027
$1. \\a. 4 + 5x < 3x + 9 \\ 2x < 5 \\ x < \frac{5}{2} \\ b. \\ c. \frac{x}{x - 4} = 12 \\ x = 12(x - 4) \\ x = 12x - 48 \\ - 11x = - 48 \\ x = \frac{48}{11}$
$2. \\ a. {x}^{2} + \sqrt{x - 2} \\ {x}^{2} + x - 2 \geqslant 0 \\ (x - 1)(x + 2) \geqslant 0 \\ x = 1 \: v \: x = - 2 \\ b. \\ c. {x}^{2} \geqslant 5 \\ x \geqslant \sqrt{5}$
$3. \\ fog = ({ {x}^{2} })^{2} + 2( {x}^{2} ) \\ fog = {x}^{4} + 2 {x}^{2} \\ gof = { ({x}^{2} + 2x)}^{2} \\ gof = {x}^{4} + 4 {x}^{3} + 4 {x}^{2}$
4. ??? ( belum pernah diajarin)
5.
$5. \\ a. \frac{ {(x + 2)}^{2} - 4 }{2x - 4} \\ \frac{ {x}^{2} + 4x + 4 - 4}{2x - 4} \\ \frac{ {x}^{2} + 4x}{2x - 4} \\ diturunin \\ \frac{2x + 4}{2} \\ \frac{2(2) + 4}{2} \\ \frac{8}{2} = 4 \\ b.diturunkan \\ \frac{4 {x}^{3} + 6 {x}^{2} - 2x}{3} \\ \frac{4 {(1)}^{3} + 6 {(1)}^{2} - 2(1)}{3} \\ \frac{4 + 6 - 2}{3} \\ \frac{8}{3}$
Maaf kalo salah, semoga membantu
yg no 1 dan 2 udh agak lupa2 dan kurang bisa.
maaf kalo dpt nilai jelek

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fanny027 udh lulus

fanny027 harusnya kuliah cuma tahun dpn

IIRomeII owh baru llus SMa.. tinggal daerah mna??

fanny027 tangerang

fanny027 udh semester brp?

IIRomeII baru smster 1.. hehe

fanny027 jurusan apa?

IIRomeII informatika..

IIRomeII kalkulus sma fisika itu matkul utama kita

fanny027 oh. susah jg, fisika belajar jg? ttg yg mana?

Fanny027... tolong di cek

Fanny027 ini jwaban aku.. Coba cek

Bgaimana penyelesaiannya.. tolong pencerahannya

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