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[ 2 x 3 = 6] dan [ 2 + 3 = 5]
(2x + 3) (x + 1)
b. 3x^2 + 7x + 2
[ 1 x 6 = 6] dan [ 1 + 6 = 7]
(3x + 1) (x + 2)
c. 2n^2 - 7n + 3
[ -1 x -6 = 6] dan [-1 + -6 = -7]
(2n - 1) (n - 3)