Question

Faktorkan bentuk aljabar berikut. 1) 8ab -12abc +16bc..2) 49x6 - y²..3) 1-81x²

Tolong yaa jawaban nya

Answer 1

1)
= 8ab - 12abc + 16bc
= 4(2ab) - 4(3abc) + 4(4bc)
= 4( 2ab - 3abc + 4bc )
= 4b (2a - 3ac + 4c)

2)
= 49x⁶ - y²
= (7x³)²  -  y²
= (7x - y)(7x + y)

3)
= 1 - 81x²
= 1 - (9x)²
= (1 - 9x)(1 + 9x)

Answer 2

1.  8ab - 12abc + 16 bc = 4b (2a - 3ac + 4c)
2. 49x^6 - y^2 = (7x - y)(7x+y)
3. 1 - 81x^2 = ( 1 -9x)(1 + 9x)