Question

Faktorkan:
a.4x² - 12x + 9
b.3x² + 3x - 6
c.2x² - 5x - 3
Tolong, pake caranya ya,, terimakasih banyak..

Answer 1

B. 3x^2 + 3x - 6 = 0 (dibagi 3)
= x^2 + x - 2
= (x + 2)(x - 1)
x1 : x + 2 = 0
x = -2
x2 : x - 1 = 0
x = 1

Answer 2

A. 4x^2-12x+9
(2x-3)       (2x-3)
2x-3= 0      2x-3
2x= 3         2x= 3
x= 3/2          x=3/2
b.3x^2+3x-6
(3x-3)           (x+2)
3x-3 = 0         x+2 = 0
3x = 3            x = -2
x = 3/3
x = 1
c. 2x^2-5x-3
(2x+1)         (x-3)
2x+1= 0        x-3= 0
2x= -1           x= 3
x= -1/2