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=> (x+4)(x-3) | 4 |-3 | 1 |
b)x² - x -6 | ac=-6 |jml|
=> (x+2)(x-3) | 2 |-3 | -1|
Jdi'in yg terbaik yh...Please!
b. x²-x-6 >>>> (x-3)(x+2)
semoga membantu:)