Respuesta:
x+2≠0
[tex]y = \frac{ - \sqrt{5 {x}^{2} + 12x + 4 - x - 2 } }{2(x + 2)} \\ \\ - \sqrt{5 {x}^{2} + 12x + 4 - x - 2.0} [/tex]
[tex]x = - \frac{2}{5} y \: \: \: = - \frac{1}{2} [/tex]
y=-2,. x=-4
y=-1 ,. x=0
Resultado
↓
-4
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Respuesta:
x+2≠0
[tex]y = \frac{ - \sqrt{5 {x}^{2} + 12x + 4 - x - 2 } }{2(x + 2)} \\ \\ - \sqrt{5 {x}^{2} + 12x + 4 - x - 2.0} [/tex]
[tex]x = - \frac{2}{5} y \: \: \: = - \frac{1}{2} [/tex]
y=-2,. x=-4
y=-1 ,. x=0
Resultado
↓
-4
. SALUDOS!