Question

Factorizar... por fa
a. x3 + 27
b. m 5 + 1
c. x7 + x7
d. m7 - 1​

Answer 1

Verified answer

[tex]m^{4}[/tex]Respuesta:

a= ( + 3 ) ( 2 − 3 + 9 )

b=(m+1)( 4 − ³+ ² − + 1 )

c=2[tex]x^{7}[/tex]

d=(m-1)([tex]m^{6}+m^{5}+m^{4}[/tex]+m³+m²+m+1)

Explicación paso a paso:

a: ³-3x²+9x+3x²-9x+27

x(x²-3x+9)+3(x²-3x+9)

( + 3 ) ( 2 − 3 + 9 )

b: [tex]m^{5}-m^{4}[/tex] +m³-m²+m+[tex]m^{4}[/tex]-m³+m²-m+1

[tex]m^{5}-m^{4}[/tex] +m³-mm+m+[tex]m^{4}[/tex]-m³+m²-m+1

[tex]m^{5}[/tex]-mm³+m³-mm+m+m+[tex]m^{4}[/tex]-m³+m²-m+1

m([tex]m^{4}[/tex]-m³+m²-m+1)+[tex]m^{4}[/tex]-m³+m²-m+1

m([tex]m^{4}[/tex]-m³+m²-m+1)+1([tex]m^{4}[/tex]-m³+m²-m+1)

(m+1)( 4 − ³+ ² − + 1 )

c:solo se combinan los términos semejantes

d: [tex]m^{7}+m^{6}+m^{5}+m^{4}[/tex]+m³+m²+m-[tex]1m^{6}-1m^{5 }-1m^{4}[/tex]-1m³-1m²-m-1

m([tex]m^{6}+m^{5}+m^4[/tex]+m³+m²+m+1)-1([tex]m^{6}+m^{5}+m^4[/tex]+m³+m²+m+1)

(m-1)([tex]m^{6}+m^{5}+m^{4}[/tex]+m³+m²+m+1)

ESPERO Y TE SIRVA DAME CORONITA PORFA