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Caso.
Factor comun por agrupacion de terminos.
10a + 15b + 20 - 6ax - 9bx - 12x = Agrupas
(10a + 15b + 20) - (6ax + 9bx + 12x) = Sacas factor comun 5 Y 3x
5(20 + 3b + 4) - 3x(2a + 3b + 4) = Sacas factor comun (2a + 3b + 4)
(2a + 3b + 4)(5 - 3x)
Respuesta.
(2a + 3b + 4)( 5 - 3x)