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x³ + 10x² + 25x = Sacas factor comun x
x(x² + 10x + 25) = El parentesis es un TCP a² + 2ab + b² = (a + b)²
x(x² + 2x(5) + 5²) =
x (x + 5)²
x² - 4x - 45 = Trinomio de la forma x² + bx + c
x -9
x +5
(x - 9)(x + 5)