Respuesta:
[tex]x^2+7x+10=\left(x+5\right)\left(x-2\right)[/tex]
[tex]\mathrm{Calculamos:}[/tex]
[tex]\left(x+5\right)\left(x-2\right)=x^2+3x-10[/tex]
[tex]x^2+7x+10=x^2+3x-10[/tex]
[tex]x^2+7x=x^2+3x-20[/tex]
[tex]\mathrm{Restamos \ x^2+3x:}[/tex]
[tex]x^2+7x-\left(x^2+3x\right)=x^2+3x-20-\left(x^2+3x\right)[/tex]
[tex]4x=-20[/tex]
[tex]\frac{-20}{4}=-5[/tex]
Solución:
[tex]\boxed{\text{x}=-5}[/tex]
Saludos...
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Verified answer
Respuesta:
[tex]x^2+7x+10=\left(x+5\right)\left(x-2\right)[/tex]
[tex]\mathrm{Calculamos:}[/tex]
[tex]\left(x+5\right)\left(x-2\right)=x^2+3x-10[/tex]
[tex]x^2+7x+10=x^2+3x-10[/tex]
[tex]x^2+7x=x^2+3x-20[/tex]
[tex]\mathrm{Restamos \ x^2+3x:}[/tex]
[tex]x^2+7x-\left(x^2+3x\right)=x^2+3x-20-\left(x^2+3x\right)[/tex]
[tex]4x=-20[/tex]
[tex]\frac{-20}{4}=-5[/tex]
Solución:
[tex]\boxed{\text{x}=-5}[/tex]
Saludos...