Hola! :3
Factorizamos por aspa simple:
x² - 2bx + b²
↓ ↓
x -b
Entonces:
x² - 2bx + b² = (x - b)(x - b)
x² - 2bx + b² = (x - b)²
Comprobamos sabiendo que:
(a + b)² = a² + 2ab + b²
(a - b)² = a² - 2ab + b²
Reemplazamos:
(x - b)² = x² - 2xb + b²
(x - b)² = x² - 2bx + b²
Espero haberte ayudado :D
Atte: Jean07122006
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Hola! :3
Factorizamos por aspa simple:
x² - 2bx + b²
↓ ↓
x -b
x -b
Entonces:
x² - 2bx + b² = (x - b)(x - b)
x² - 2bx + b² = (x - b)²
Comprobamos sabiendo que:
(a + b)² = a² + 2ab + b²
(a - b)² = a² - 2ab + b²
Reemplazamos:
(x - b)² = x² - 2xb + b²
(x - b)² = x² - 2bx + b²
Espero haberte ayudado :D
Atte: Jean07122006