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x^4-x^3-7 x^2+x+6 = 0
(x-3) (x-1) (x+1) (x+2) = 0
x-3 = 0 o x-1 = 0 o x+1 = 0 o x+2 = 0
x = 3 o x-1 = 0 o x+1 = 0 o x+2 = 0
x = 3 o x = 1 o x+1 = 0 o x+2 = 0
x = 3 o x = 1 o x = -1 o x+2 = 0
x = 3 o x = 1 o x = -1 o x = -2
saludos