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1 0 -10 -20 -16
-2 -2 4 12 16
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1 -2 -6 -8 0
(x+2) x³ -2x² -6x -8
x⁴ - 10x² - 20x - 16 Agrupamos
(x⁴ - 16) - (10x² + 20x) = El 1er parentesis es una diferencia de cuadrado
a² - b² ( (a + b)(a - b). El 2do sacaos factor comun 10x
(x² + 4)(x² - 4) - 10x( x + 2) = x² - 4 es una diferencia de cuadrados
(x² + 4)(x + 2)(x - 2) - 10x (x + 2)= Sacamos factor comun ( x + 2)
(x + 2) [(x² + 4)(x - 2) - 10x] =
(x + 2) ( x³ + 4x - 2x² - 8 - 10x)=
(x + 2)( x³ - 2x² - 6x - 8)