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Bab Fungsi KomposisiMatematika SMA Kelas X
f(2x - 1) = 4x + 5
2x - 1 = 3
2x = 3 + 1
x = 4/2
x = 2
4x + 5 = 4 . 2 + 5
= 8 + 5
= 13
2. lalu cari x nya
2x-1=y
2x=y+1
x=(y+1)/2
3. subtitusikan x kedalam fungsi f(y)
f(y)= 4((y+1)/2)+5
f(y)=(4y+4)/2)+5
f(y)=2y+2+5
f(y)=2y+7
4. kembalikan f(y) menjadi f(x)
f(y)=2y+7
f(x)=2x+7
5. maka f(3)..
f(x)=2x+7
f(3)=2(3)+7
f(3)=6+7
f(3)=13