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Verified answer
A=f/ma=12-8/10
a=0,4 kearah F1
↪F1 = 12 N (Arah kanan)
↪F2 = 8 N (arah kiri)
↪m = 10 kg
Ditanya :
↪percepatan benda
Jawaban
=========
EF = F1 - F2
..... = 12 - 8
..... = 4 N ( kearah kanan)
➡EF (sigam F)
Maka, besar percepatan benda adalah
a = EF/m
a = 4/10
a = 0,4 m/s → arah gaya ke kanan
a → searah F1
Jawaban A.
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