Respuesta:
[tex]y=\frac{4}{5}x+\frac{12}{5}[/tex]
Explicación paso a paso:
[tex]\mathrm{Encontrar\:la\:recta\:}\mathbf{y=mx+b}\mathrm{\:que\:pasa\:por\:}\left(2,\:4\right)\mathrm{,\:}\left(7,\:8\right)\\\\\mathrm{Construir\:la\:ecuacion\:de\:la\:recta\:}\mathbf{y=mx+b}\mathrm{\:donde\:}\mathbf{m}=\frac{4}{5}\mathrm{\:y\:}\mathbf{b}=\frac{12}{5}\\\\y=\frac{4}{5}x+\frac{12}{5}[/tex]
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Respuesta:
[tex]y=\frac{4}{5}x+\frac{12}{5}[/tex]
Explicación paso a paso:
[tex]\mathrm{Encontrar\:la\:recta\:}\mathbf{y=mx+b}\mathrm{\:que\:pasa\:por\:}\left(2,\:4\right)\mathrm{,\:}\left(7,\:8\right)\\\\\mathrm{Construir\:la\:ecuacion\:de\:la\:recta\:}\mathbf{y=mx+b}\mathrm{\:donde\:}\mathbf{m}=\frac{4}{5}\mathrm{\:y\:}\mathbf{b}=\frac{12}{5}\\\\y=\frac{4}{5}x+\frac{12}{5}[/tex]