Respuesta:
[tex]\:x+\frac{3}{2}\:+\:2\:=\:x\:+\:\frac{2}{5}\:+4\\\\x+\frac{3}{2}+2-x=x+\frac{2}{5}+4-x\\\\\frac{3}{2}+2=\frac{2}{5}+4\\\\\frac{7}{2}=\frac{22}{5}\\\\Los\:lados\:no\:son\:iguales\\\\\mathrm{Sin\:solucion}[/tex]
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Respuesta:
[tex]\:x+\frac{3}{2}\:+\:2\:=\:x\:+\:\frac{2}{5}\:+4\\\\x+\frac{3}{2}+2-x=x+\frac{2}{5}+4-x\\\\\frac{3}{2}+2=\frac{2}{5}+4\\\\\frac{7}{2}=\frac{22}{5}\\\\Los\:lados\:no\:son\:iguales\\\\\mathrm{Sin\:solucion}[/tex]