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TanФ = 3/2
TanФ = 1,5
Cateto opuesto = h = altura del edificio
Cateto adyacente = 24m
TanФ = Cateto opuesto/Catero adyacente
1,5 = h/24m
24m * 1,5 = h
36m = h
La altura del edificio es de 36m
∡x = (AD - BC)/2
∡x = (a° + 60° - (20° + a°))/2
∡x = (a° + 60° - 20° - a°)/2
∡x = 40°/2
∡x = 20°
El ángulo x = 20°