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x: Celia
y: Quique
x+y= 14 ----(Ec. 1)
x+1= 2y
Despejamos x:
x= 2y-1 ----(Ec. 2)
Sustituyendo Ec. 2 en Ec. 1
x+y= 14
2y-1+y= 14
3y= 14+1
3y= 15
y= 15/3
y= 5
x= 2y-1
x= 2(5)-1
x= 10-1
x= 9
Respuesta.
Celia (x) tiene 9 €
Quique (y) tiene 5 €
Comprobación:
x+1= 2y
9+1= 2(5)
10= 10