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por dato se tiene que:
x(x+1) = x+x+1+ 41
x(x+1) = 2x + 42
x² + x - 2x - 42 = 0
x² - x - 42 = 0
x.........-7
x..........6
(x-7)(x+6) = 0
de aqui se tiene que:
x = 7
x = -6
por lo tanto existen 2 alternativas que satisfacen el problema
7 y 8
-6 y -5