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a= 5; b=0; c=12
x= [-b±√ (b² - 4ac)]/(2a)
x= [-0±√ (0² - 4*5*12)]/(2*5)
x= [±√ (-240)]/10 ; al ser negativo el discriminante, las raíces son imaginarias
x= ±15.4919 i / 10
x1= 1.5492 i; x2= -1.5492 i