Explicación paso a paso:
[tex]3x + 5y = 15 \\ 4x + 10y = - 20 \\ 3x = 15 - 5y \\ x = \frac{15 - 5y}{3} \\ 4( \frac{15 - 5y}{3} ) + 10y = - 20 \\ \frac{60 - 20y}{3} + 10y = - 20 \\ 60 - 20y + 30y = - 60 \\ 10y = - 60 - 60 \\ 10y = - 120 \\ y = \frac{ - 120}{10} = - 12 \\ y = - 12 \\ x = \frac{15 - 5( - 12)}{3} \\ = \frac{15 + 60}{3} \\ x = \frac{75}{3} = 25 \\ luego \: x = 25 \: y \: \: y = - 12[/tex]
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Verified answer
Explicación paso a paso:
[tex]3x + 5y = 15 \\ 4x + 10y = - 20 \\ 3x = 15 - 5y \\ x = \frac{15 - 5y}{3} \\ 4( \frac{15 - 5y}{3} ) + 10y = - 20 \\ \frac{60 - 20y}{3} + 10y = - 20 \\ 60 - 20y + 30y = - 60 \\ 10y = - 60 - 60 \\ 10y = - 120 \\ y = \frac{ - 120}{10} = - 12 \\ y = - 12 \\ x = \frac{15 - 5( - 12)}{3} \\ = \frac{15 + 60}{3} \\ x = \frac{75}{3} = 25 \\ luego \: x = 25 \: y \: \: y = - 12[/tex]