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Rojas=x+11
x+(x+11)=53
2x+11=53
2x=53-11
2x=42
x=21 --->Cantidad de bolas azules
A + A + 11 = 53, resolviendo tenemos que:
2A = 53 - 11
2A = 42
A = 42/2
A = 21
Hay 21 bolas azules y 32 bolas rojas. 21 + 32 = 53 bolas en total.
Espero haberte ayudado!