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Triciclos = n
m + n = 51
2m + 3n = 133
Despejo m en 1
m + n = 51
m = 51 - n
Sustituyo m en 2
2m + 3n = 133
2 (51 - n) + 3n = 133
102 - 2n + 3n = 133
- 2n + 3n = 133 - 102
n = 31
Sustituyo el valor de n en el despeje de m
m = 51 - n
m = 51 - 31
m = 20
Solcuión. Hay 20 bicicletas y 31 triciclos
B=51-T
Reemplazando este valor en:
3T+2B=133
3T+2(51-T)=133
3T+102-2T=133
T=31
HAY 31 TRICICLOS