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Tenemos.
Total del trayecto = x
recorrido el 1er dia = 2/3 de x = 2/3 * x = 2x/3
Lo que queda por recorrer = x - 2x/3 = 3x/3 - 2x/3 = (3x - 2x)/3 = x/3
Recorrido el 2do dia = 2/5 de x/3 = 2/5 * x/3 = 2x/15
El 3er dia = 35km
x - 2x/3 - 2x/15 = 35 El mcm de los denominadores 3 y 5 es 15
15x/15 - 10x/15 - 2x/15 = 35
(15x - 10x - 2x)/15 = 35
3x/15 = 35
3x = 35* 15
3x = 525
x = 525/3
x = 175km
Respuesta.
El trayecto mide 175 km